Q22 · Atomic Structure
Problem
JEE Advanced 2012 Paper 1 — Chemistry Q22. (Full statement in PDF — open reference.)
1. Solution outline
KE in 2nd Bohr orbit = h²/(32π²ma₀²).
Hints
- KE in 2nd Bohr orbit = h²/(32π²ma₀²).
Answer
(C)
22 of 60
JEE Advanced 2012 Paper 1 — Chemistry Q22. (Full statement in PDF — open reference.)
KE in 2nd Bohr orbit = h²/(32π²ma₀²).
(C)
22 of 60